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23^(4x-12)=1/23^(2x)
We move all terms to the left:
23^(4x-12)-(1/23^(2x))=0
Domain of the equation: 23^2x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
23^(4x-12)-1/23^2x=0
We multiply all the terms by the denominator
(23^(4x-12))*23^2x-1=0
We move all terms containing x to the left, all other terms to the right
(23^(4x-12))*23^2x=1
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